Equasion for different card positions?

formula

Elite Member
Jan 8, 2010
968
5
Are there any math geniuses out there that know the correct sum to calculate how many different positions a card can be in? I'm not talking about 1 in 52, I'm talking about every possible permutation of every single card at any one time. Each card can be in 52 different positions and each position has 52 different arrangements in 52 different sequences...something along those lines.

Appreciate any help. I would like to know that fact.
 

CAndrew

Elite Member
Jan 12, 2011
267
0
"What this means, in practical terms, is that every time you shuffle a deck of 52 cards, you get a new arrangement of the cards that has never been seen by anyone before, and will never occur again! "

Pretty sure someone other than me has had a perfect faro shuffle with a brand new deck lol. Just keep in mind that even though statistics says it should never happen anytime soon, doesnt mean it hasnt.
 

S.G

Feb 9, 2010
664
1
Here is the number:


80,658,175,170,943,878,571,660,636,856,403,766,975,289,505,440,883,277,824,000,000,000,000
 
Last edited by a moderator:

formula

Elite Member
Jan 8, 2010
968
5
Awesome, just what I was looking for Rich23 and thanks for posting the actual number incase I was one of those people too lazy to look at the link Suhaas.
 
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