Saturday Night Contest - Guess Again

[mchoi999]

math.

Well, its (55*55)/2 to account for the doubles. Dividing by two will kill the unique issue. Or should.

-ThrallMind

not true.

the total number of events is just 55*54/2 + 55. think about it. make two sets. where we have two different cards and the same cards.

different cards:
55 choose 2.
55*54/2

same cards:
we have 55 pairs.

stop playing with cards and study math!
i'm in stat right now.

 

[ThrallMind]

2x Ace of Spades

2x Ace of Hearts

2x Ace of Diamonds
2x 6 of Diamonds

2x Ace of Clubs
2x 2 of Clubs

2x Double Backers

2x Jokers

2x Any of the Jacks

And also... The ad cards have no back. They are the ad on both sides.

-ThrallMind

 

[PlethZorb]

Yo.

Guess 1: 6 of Spades/ 9 of Diamonds

Guess 2: King of Clubs/ 2 of Hearts

Guess 3: Ace of Spades/ Jack of Clubs

yeaaah

 

[Mega]

Second guess:

2 jokers

 

[Bao Hoang]

1:: Ace of Spades // Ace of Spades
2:: Joker // Joker
3:: Seven of Diamonds // Seven of Diamonds

Peace

2 seven of diamonds?

 

[jesse.ecm]

my guesses

1. 2 of hearts and ace of clubs
2. queen of diamonds and 3 of clubs
3. 3 of clubs and 2 of hearts

 

[JDENredden]

G1=2 spades and jack of spades.
G2=2 hearts and 7 clubs.
G3=10 clubs and 8 clubs.

G4=king hearts and kind of clubs.

JDEN

 

[DannyT]

both queen of diamonds?

 

[ThrallMind]

not true.

the total number of events is just 55*54/2 + 55. think about it. make two sets. where we have two different cards and the same cards.

different cards:
55 choose 2.
55*54/2

same cards:
we have 55 pairs.

i'm in stat right now.

Actually, (55*54) + 55 should do it.

(Uniques) + (Cases where we can have a double)

-ThrallMind

 

[adjones]

Last guess for real this time:

6 of Spades and 10 of Diamonds

Thanks for the extra guess, Wayne!

 

[liamA10]

My extra Guess:

A double backer and a blank card

Weird guess, but owell

 

[TKK]

Omg! It seems that both my first and second guesses had been taken up by the others. I'm wondering if I should look through all of the posts, compile them into a list, and thoroughly analyse the guesses, and come up with a very educated guess using the process of elimination? By but the time I had done so, some others might just have had their wild guesses right! So I might just as well have a wild guess here... Lol!

Guess 3: Two Nines of Hearts

Don't know if anyone had the samething AGAIN before me.

 

[DannyT]

guys, I think we should all just start guessing before it hits 11.
We have a half hour to figure out what the two cards are.

Deal Or No Deal?

 

[ThrallMind]

Doubles
======

Spades
Ace
Jack

Hearts
Ace
9
Jack

Diamonds
Ace
6
7
Jack
Queen

Clubs
Ace
2
Jack

2x Double Backers

2x Jokers

And also... The ad cards have no back. They are the ad on both sides.

-ThrallMind

 

[DannyT]

Both Queen of Spades!!

 

[FatalAce]

Doubles
======

Spades
Ace
Jack

Hearts
Ace
9
Jack

Diamonds
Ace
6
7
Jack
Queen

Clubs
Ace
2
Jack

2x Double Backers

2x Jokers

And also... The ad cards have no back. They are the ad on both sides.

-ThrallMind

Wow. ThrallMind. You really are putting a lot of thought into this very simple contest. =)

 

[liamA10]

Man, its gonna take Wayne ages to read all these guesses......

 

[mchoi999]

i know stat.

Actually, (55*54) + 55 should do it.

(Uniques) + (Cases where we can have a double)

-ThrallMind

i tell you sir, it does not. haha.

combinations (order does not matter a.k.a king of spades-ace of spades is equal to ace of spades-king of spades)-

nCx (n choose x)
n!/(x!*(n-x)!)
so (55*54*...)/((53*52*51..)(2*1))

permutations (order does matter a.k.a king of spades-ace of spades is NOT equal to ace of spades-king of spades)

nPx
simply. n!/(n-x)!


i stand by 55*54/2 + 55 = 1540 i think

 

[DavidOchs]

guess 4

TWO ACE OF CLUBS

 

[username]

My fourth and final guess.

two 3 of clubs