theory11 — Magic Tricks & the World's Finest Playing Cards

Jazz Aces :: Peter Kane

D

Donald C.

Nov 10, 2007
1,706
1
I have posted this same trick several times, and have tried to fix everyhting flawed in it. Please tell me if you see anything that can be improved if not I finally perfected it after almost a year of intensive work.

http://www.youtube.com/watch?v=PGkAre1VPxU

Things to look at:
Was the technique good?
How was were the elmsey counts?
Double Lifts?
Patter?
Words did they get srcambled up?

Thank you
 
a subtlety i use for performing jazz aces (don't really perform it prefer gimmicked assembly's) i use blank cards and reverse spread the 4 cards in my hand ;) its a very nice subtlety
 
sleights looked perfect to me.
Everything looked good

i just thought the performance was kind of boring.

but thats just my style.
 
jok3r said:
sleights looked perfect to me.
Everything looked good

i just thought the performance was kind of boring.

but thats just my style.
Click to expand...

Thank you for the comments, I would like to know what was boring about the presentation so I can change it.
Thank you.
 
magicman1212 said:
Thank you for the comments, I would like to know what was boring about the presentation so I can change it.
Thank you.
Click to expand...


Soccer%20Fail.jpg




Nope, I do think the patter was fine.
 
D ICE R said:
lets just refer to it as (epic fail)^3
Click to expand...

a little extreme dont ya think. triple epic fail would be the quivalent of 3*(epic fail) by the distributive property, which is (epic fail) + (epic fail) + (epic fail) whereas (epic fail)^3 would actually be (epic fail) * (epic fail) * (epic fail). A cubic of a fail on the order of epic is almost unfathomable.

(I have no idea wtf i just said)
 
Jo_Vision said:
a little extreme dont ya think. triple epic fail would be the quivalent of 3*(epic fail) by the distributive property, which is (epic fail) + (epic fail) + (epic fail) whereas (epic fail)^3 would actually be (epic fail) * (epic fail) * (epic fail). A cubic of a fail on the order of epic is almost unfathomable.

(I have no idea wtf i just said)
Click to expand...

whatever you just said, magicman1212 just achieved it.
 
Jo Vision I appreciate your mathematics, however, I feel that the if we were to use the notion of 3*(epic fail) the implied nature is that he failed on three separate occasions. Whilst this is true the failure is still centralised around a common value fail in this instance. If we were to take the variables of the epic nature around the one true know of fail(ure) we would get the following idea;

Epic(1) Fail * Epic(2) Fail * Epic(3) Fail

Rewritten in an equation:

This thread = [Epic(1)*Epic(2)*Epic(3)]*Fail^3
 
Jo_Vision said:
a little extreme dont ya think. triple epic fail would be the quivalent of 3*(epic fail) by the distributive property, which is (epic fail) + (epic fail) + (epic fail) whereas (epic fail)^3 would actually be (epic fail) * (epic fail) * (epic fail). A cubic of a fail on the order of epic is almost unfathomable.

(I have no idea wtf i just said)
Click to expand...

D ICE R said:
Jo Vision I appreciate your mathematics, however, I feel that the if we were to use the notion of 3*(epic fail) the implied nature is that he failed on three separate occasions. Whilst this is true the failure is still centralised around a common value fail in this instance. If we were to take the variables of the epic nature around the one true know of fail(ure) we would get the following idea;

Epic(1) Fail * Epic(2) Fail * Epic(3) Fail

Rewritten in an equation:

This thread = [Epic(1)*Epic(2)*Epic(3)]*Fail^3
Click to expand...

I am sorry but it is (epic + fail)³.

Let's say epic=x and fail=y

So it becomes (x+y)³

Because of the distributive properties of addition or subtraction in a bracket, we must multiply everything through one-by-one.

(x+y)³ is really: (x+y)(x+y)(x+y)

(x+y)(x+y)(x+y)

x² +2xy +y²(x+y)

x³ +x²y +2x²y 2xy² +xy² +y³

x³ + 3x²y +3xy² +y³

Now we can substitute the epic and the fail back in for the x's and y's, respectively.

epic³ + 3epic²fail +3epicfail² + fail³

---------------------------------------------------------------

Back to Jo_Vision's point. Now I agree that (epic fail)³ is unfathomable, but (epic + fail)³ = epic³ + 3epic²fail +3epicfail² + fail³. That is simply inscrutable, incomprehensible, enigmatic and indecipherable...
 
D ICE R said:
Jo Vision I appreciate your mathematics, however, I feel that the if we were to use the notion of 3*(epic fail) the implied nature is that he failed on three separate occasions. Whilst this is true the failure is still centralised around a common value fail in this instance. If we were to take the variables of the epic nature around the one true know of fail(ure) we would get the following idea;

Epic(1) Fail * Epic(2) Fail * Epic(3) Fail

Rewritten in an equation:

This thread = [Epic(1)*Epic(2)*Epic(3)]*Fail^3
Click to expand...
So that would make epic a state variable. This brings in an interesting perplexity

shooting_rubber said:
I am sorry but it is (epic + fail)³.

Let's say epic=x and fail=y

So it becomes (x+y)³

Because of the distributive properties of addition or subtraction in a bracket, we must multiply everything through one-by-one.

(x+y)³ is really: (x+y)(x+y)(x+y)

(x+y)(x+y)(x+y)

x² +2xy +y²(x+y)

x³ +x²y +2x²y 2xy² +xy² +y³

x³ + 3x²y +3xy² +y³

Now we can substitute the epic and the fail back in for the x's and y's, respectively.

epic³ + 3epic²fail +3epicfail² + fail³
Click to expand...

Good pickup, but I was assuming that epic is an order of magnitude not an additive property. We may need to bring in an expert in the ways of internet lingo to explain whether epic should be multiplied or added. This could have huge bearing on our calculations. We are on the verge of something huge here, lets take all the precautions necessary to ensure our formulation is indeed right. (Did you do those supscripts in here or copy and paste that from word or something?)
 
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What the hell is wrong with me? I am sitting here discussing the correct formulation of "triple epic fail" whilst i should be going over shear stress associated with extrusion so I don't fail this Manufacturing test that i have to take in 6 HOURS. Yeah, i need some type of mental help.
 
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