a little extreme dont ya think. triple epic fail would be the quivalent of 3*(epic fail) by the distributive property, which is (epic fail) + (epic fail) + (epic fail) whereas (epic fail)^3 would actually be (epic fail) * (epic fail) * (epic fail). A cubic of a fail on the order of epic is almost unfathomable.
(I have no idea wtf i just said)
Jo Vision I appreciate your mathematics, however, I feel that the if we were to use the notion of 3*(epic fail) the implied nature is that he failed on three separate occasions. Whilst this is true the failure is still centralised around a common value fail in this instance. If we were to take the variables of the epic nature around the one true know of fail(ure) we would get the following idea;
Epic(1) Fail * Epic(2) Fail * Epic(3) Fail
Rewritten in an equation:
This thread = [Epic(1)*Epic(2)*Epic(3)]*Fail^3
I am sorry but it is (epic + fail)³.
Let's say epic=x and fail=y
So it becomes (x+y)³
Because of the distributive properties of addition or subtraction in a bracket, we must multiply everything through one-by-one.
(x+y)³ is really: (x+y)(x+y)(x+y)
(x+y)(x+y)(x+y)
x² +2xy +y²(x+y)
x³ +x²y +2x²y 2xy² +xy² +y³
x³ + 3x²y +3xy² +y³
Now we can substitute the epic and the fail back in for the x's and y's, respectively.
epic³ + 3epic²fail +3epicfail² + fail³
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Back to Jo_Vision's point. Now I agree that (epic fail)³ is unfathomable, but (epic + fail)³ = epic³ + 3epic²fail +3epicfail² + fail³. That is simply inscrutable, incomprehensible, enigmatic and indecipherable...